1.What Is The Percent By Volume Of A Solution Formed By Mixing 35ml Of Isopropanol With 55ml Water?,
1.what is the percent by volume of a solution formed by mixing 35ml of isopropanol with 55ml water?
Answer:
Percentage by Volume
Problem #1
Given:
volume of solute (isopropanol) = 25 mL
volume of solvent (water) = 45 mL
Asked: % volume
Equation: % volume = \frac{volume of solute}{volume of solution}
volumeofsolution
volumeofsolute
x 100%
Solution:
% volume = \frac{volume of solute}{volume of solution}
volumeofsolution
volumeofsolute
x 100%
= \frac{volume of solute}{volume of solute +solvent}
volumeofsolute+solvent
volumeofsolute
x 100%
= \frac{25 mL}{25 mL + 45mL}
25mL+45mL
25mL
x 100%
= \frac{25 mL}{70 mL}
70mL
25mL
x 100%
= 0.3571 x 100%
= 35.71 %
Problem #2
Given:
volume of solute (acetic acid) = 160 mL
volume of solution (stop bath) = 650 mL
Asked: % volume
Equation: % volume = \frac{volume of solute}{volume of solution}
volumeofsolution
volumeofsolute
x 100%
Solution:
% volume = \frac{volume of solute}{volume of solution}
volumeofsolution
volumeofsolute
x 100%
= \frac{160 mL}{650mL}
650mL
160mL
x 100%
= 0.2462 x 100%
= 24.62 %
Explanation:
Solutions are homogeneous mixtures that are made of solute dissolved in a solvent. The amount of solute in the solution tells us of the concentration of the solution. This can be expressed either as percent mass, percent volume or percent mass/volume. If the solute and solvent are in liquid or gas, percent volume may be used. The volume percent of a solution is defined as the ratio of the volume of solute that is present in a solution, relative to the volume of the solution, as a whole. This ratio then is multiplied by 100 to get the percent volume:
% volume = \frac{volume of solute}{volume of solution}
volumeofsolution
volumeofsolute
x 100%
Since a solution is a combination of a solute and a solvent, the volume of a solution, as a whole, is equal to the sum of the volumes of the solute and the solvent that it contains. Therefore, we can use the following equation to
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